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Solution


Q.

The volume of hydrogen liberated at STP by treating 2.4 g magnesium with excess of hydrochloric acid is ______ ×10-2 L               [2023]

Given: Molar volume of gas is 22.4 L at STP.

           Molar mass of magnesium is 24 g mol-1

Ans.

(224)

Mg+2HCl→MgCl2+H2↑

1 mole         1 mole

w=2.4 g

  =0.1 mole    0.1 mole

1 mole of gas at STP

   =22.4 lit.

∴  0.1 mole of gas=0.1×22.4

       =2.24 lit=224×10-2 litre