The volume of HCl, containing 73 g , required to completely neutralise NaOH obtained by reacting 0.69 g of metallic sodium with water is _____ mL. (Nearest Integer (Given: Molar masses of Na, Cl, O, H, are 23, 35.5, 16 and 1 g respectively)

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Solution

Q.
The volume of HCl, containing 73 g $L^{- 1}$ , required to completely neutralise NaOH obtained by reacting 0.69 g of metallic sodium with water is _____ mL. (Nearest Integer

(Given: Molar masses of Na, Cl, O, H, are 23, 35.5, 16 and 1 g ${mol}^{- 1}$ respectively) [2023]

Ans.
(15)

$2 Na + 2 H_{2} O ⟶ 2 NaOH + H_{2}$

$Number of moles of Na = Number of moles of NaOH$

$n_{NaOH} = \frac{0.69}{23} = 0.03$

$NaOH + HCl ⟶ NaCl + H_{2} O$

$Moles of HCl = moles of NaOH$

${(Molarity \times V)}_{HCl} = Number of moles of NaOH$

$(\frac{73}{36.5 \times 1}) \times V = 0.03$

$\Rightarrow V = 15 \times 10^{- 3} Lit = 15 mL.$

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