Q.

The vector a→=-i^+2j^+k^ is rotated through a right angle, passing through the y-axis in its way and the resulting vector is b→. Then the projection of 3a→+2 b→ on c→=5i^+4j^+3k^ is             [2023]

1 32  
2 1  
3 23  
4 6  

Ans.

(1)

 b→, a→ and j^ are coplanar.

b→=λa→+μj^=λ(-i^+2j^+k^)+μj^

   =-λi^+(2λ+μ)j^+λk^, b→·a→=0

(-i^+2j^+k^)·(-λi^+(2λ+μ)j^+λk^)=0

λ+2(2λ+μ)+λ=0⇒6λ+2μ=0⇒μ+3λ=0

b→=λa→-3λj^=λ(-i^+2j^+k^)-3λj^=λ(-i^-j^+k^)

|b→|=3|λ|=6 [∵|a→|=6]⇒|λ|=2⇒λ≠2

As for this value of λ angle between b and y-axis is not acute.

Therefore λ=-2;

3a→+2 b→=-i^+8j^+k^; |c→|=52

(3a→+2b→)·c→|c→|=(-i^+8j^+k^)·(5i^+4j^+3k^)52

=-5+32+352=3052=62=32