Q.

The vector a=-i^+2j^+k^ is rotated through a right angle, passing through the y-axis in its way and the resulting vector is b. Then the projection of 3a+2b on c=5i^+4j^+3k^ is             [2023]

1 32  
2 1  
3 23  
4 6  

Ans.

(1)

 b, a and j^ are coplanar.

b=λa+μj^=λ(-i^+2j^+k^)+μj^

   =-λi^+(2λ+μ)j^+λk^, b·a=0

(-i^+2j^+k^)·(-λi^+(2λ+μ)j^+λk^)=0

λ+2(2λ+μ)+λ=06λ+2μ=0μ+3λ=0

b=λa-3λj^=λ(-i^+2j^+k^)-3λj^=λ(-i^-j^+k^)

|b|=3|λ|=6 [|a|=6]|λ|=2λ2

As for this value of λ angle between b and y-axis is not acute.

Therefore λ=-2;

3a+2b=-i^+8j^+k^; |c|=52

(3a+2b)·c|c|=(-i^+8j^+k^)·(5i^+4j^+3k^)52

=-5+32+352=3052=62=32