The van’t Hoff factor (i) for a dilute aqueous solution of the strong electrolyte barium hydroxide is [2016]
(4)
Being a strong electrolyte, Ba(OH)2 undergoes 100% dissociation in a dilute aqueous solution,
Ba(OH)2(aq) ⟶ Ba(aq)2++2OH(aq)-
Thus, van’t Hoff factor i=3