The value of the integral ∫π245π24dx1+tan2x3 is: [2026]
(3)
I=∫π245π24dx1+tan2x3 ...(1)
Apply King
I=∫π245π24dx1+tan2(π4-x)3
I=∫π245π24dx1+cot2x3 ...(2)
Add (1) + (2) ⇒2I=∫π245π24(1) dx
I=12(π6)=π12