Q.

The value of limx→02(1-cosxcos2xcos3x3⋯cos10x10x2) is _______ .                 [2024]


Ans.

(55)

limx→02(1-cosxcos2xcos3x3…cos10x10x2)

Let f=cosxcos2xcos3x3…cos10x10

f=cosx(cos2x)1/2(cos3x)1/3…(cos10x)1/10

Taking log on both sides, we get

logf=log cosx+12cos2x+13cos3x+…+110cos10x

Differentiating w.r.t. x

1fdfdx=-tanx-tan2x…-tan10x

dfdx=-f(tanx+tan2x…+tan10x)

Using L'Hospital's Rule

limx→02(f(tanx+tan2x…+tan10x))2x                 (∵ f=1)

=1+2+…+10=55