Q.

The value of ∫-π/6π/6(π+4x111-sin(|x|+π/6))dx is equal to:        [2026]

1 8π  
2 2π  
3 6π  
4 4π  

Ans.

(4)

=2π∫0π/611-sin(x+π6)dx  let x+π6=t⇒dx=dt

=2π∫π/6π/3dt1-sint=2π∫π/6π/31+sintcos2tdt

=2π[∫π/6π/3sec2t dt+∫π/6π/3sec t tan t dt]

=2π[(tant)π/6π/3+(sect)π/6π/3]

=2π[(3-13)+(2-23)]

=2π[3+2-3]=4π