Q.

The value of -π2π2(1[x]+4)dx, where [·] denotes the greatest integer function, is            [2026]

1 760(3π-1)  
2 160(21π-1)  
3 760(π-3)  
4 160(π-7)  

Ans.

(1)

I=-π/2π/21[x]+4dx

I=-π/2-1dx2+-10dx3+01dx4+1π/2dx5

=12(-1+π2)+13(1)+14(1)+(π2-1)15

=7π20-760=760(3π-1)