The temperature at which the kinetic energy of oxygen molecules becomes double than its value at 27°C is [2023]

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Solution

Q.
The temperature at which the kinetic energy of oxygen molecules becomes double than its value at 27°C is [2023]

1 627°C

2 327°C

3 927°C

4 1227°C

Ans.
(2)

$Kinetic energy = \frac{f}{2} k T, where T is the absolute temperature.$

$If K_{1} is the kinetic energy at 27 ° C$

$and K_{2} is the kinetic energy at new temperature T .$

$\frac{K_{1}}{K_{2}} = \frac{T_{1}}{T_{2}} \Rightarrow \frac{1}{2} = \frac{300}{T}$

$T = 600 K \Rightarrow T = 327 ° C$

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