Q.

The sum of the absolute maximum and minimum values of the function f(x)=|x2-5x+6|-3x+2 in the interval [-1,3] is equal to              [2023]

1 12  
2 10  
3 24  
4 13  

Ans.

(2)

f(x)=|x2-5x+6|-3x+2

f(x)={x2-8x+8,x[-1,2]-x2+2x-4,x[2,3]

From the graph, Maximum value = 17 

Minimum value = - 7 as f(-1) = 17 and f(3)=-7

Sum of the absolute maximum and minimum values = 17-7=10