The sum of the absolute maximum and minimum values of the function f(x)=|x2-5x+6|-3x+2 in the interval [-1,3] is equal to [2023]
(2)
f(x)=|x2-5x+6|-3x+2
f(x)={x2-8x+8,x∈[-1,2]-x2+2x-4,x∈[2,3]
From the graph, Maximum value = 17
Minimum value = - 7 as f(-1) = 17 and f(3)=-7
∴ Sum of the absolute maximum and minimum values = 17-7=10