The spin-only magnetic moment value of -ion formed among Ni, Zn, Mn and Cu that has the least enthalpy of atomisation is ______. (in nearest integer) Here is equal to the number of diamagnetic complexes among and [2025]

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Solution

Q.
The spin-only magnetic moment value of ${Mn}^{+}$ -ion formed among Ni, Zn, Mn and Cu that has the least enthalpy of atomisation is ______. (in nearest integer)

Here $n$ is equal to the number of diamagnetic complexes among $K_{2} [{NiCl}_{4}], [Zn {(H_{2} O)}_{6}] {Cl}_{2}, K_{3} [Mn {(CN)}_{6}]$ and $[Cu {({PPh}_{3})}_{3} I]$ [2025]

Ans.
(0)

Zinc has least enthalpy of atomization in 3d series. So M is Zn.

$K_{2} [{NiCl}_{4}]$

$[Zn {(H_{2} O)}_{6}] {Cl}_{2}$

$K_{3} [Mn {(CN)}_{6}]$

$[Cu {({PPh}_{3})}_{3} I]$

There are two diamagnetic complexes, so $n$ = 2.
Thus the ion is $Z n^{2 +}$ . It has zero unpaired electrons, so $μ$ = 0.

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