The solubility product of BaSO 4 is 1 × 10 - 10 at 298 K. The solubility of BaSO 4 in 0.1 M K 2 SO 4 ( aq ) solution is _______ × 10 - 9 g L - 1 (Nearest Integer) Given: Molar mass of BaSO 4 is 233 g mol - 1 [2023]

Question

The solubility product of ${BaSO}_{4}$ is $1 \times 10^{- 10}$ at 298 K. The solubility of ${BaSO}_{4}$ in 0.1 M $K_{2} {SO}_{4} (aq)$ solution is _______ $\times 10^{- 9} {g L}^{- 1}$ (Nearest Integer)

Given: Molar mass of ${BaSO}_{4}$ is 233 g ${mol}^{- 1}$ [2023]

Smart Achievers · Accepted Answer

(233)

${BaSO}_{4} ⇌ \underset{s}{{Ba}^{2 +}} + \underset{s + 0.1}{{SO}_{4}^{2 -}}$

$K_{s p} = s \times (s + 0.1)$

$∵$ $s ≪ 0.1$

$∴$ $K_{s p} = 0.1 \times s$

$\frac{1 \times 10^{- 10}}{0.1} = s$

$\Rightarrow s = 1 \times 10^{- 9} mol/L$

$= 1 \times 10^{- 9} \times 233 {g mol}^{- 1} \times mol/L$

$= 233 \times 10^{- 9} {g L}^{- 1}$

Solution

Q.
The solubility product of ${BaSO}_{4}$ is $1 \times 10^{- 10}$ at 298 K. The solubility of ${BaSO}_{4}$ in 0.1 M $K_{2} {SO}_{4} (aq)$ solution is _______ $\times 10^{- 9} {g L}^{- 1}$ (Nearest Integer)

Given: Molar mass of ${BaSO}_{4}$ is 233 g ${mol}^{- 1}$ [2023]

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Solution

Q. The solubility product of BaSO4 is 1×10-10 at 298 K. The solubility of BaSO4 in 0.1 M K2SO4(aq) solution is _______ ×10-9g L-1 (Nearest Integer) Given: Molar mass of BaSO4 is 233 g mol-1 [2023]

Ans. (233) BaSO4⇌Ba2+s+SO42-s+0.1 Ksp=s×(s+0.1) ∵ s≪0.1 ∴ Ksp=0.1×s 1×10-100.1=s ⇒ s=1×10-9mol/L =1×10-9×233g mol-1×mol/L =233×10-9g L-1

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Q.
The solubility product of ${BaSO}_{4}$ is $1 \times 10^{- 10}$ at 298 K. The solubility of ${BaSO}_{4}$ in 0.1 M $K_{2} {SO}_{4} (aq)$ solution is _______ $\times 10^{- 9} {g L}^{- 1}$ (Nearest Integer)

Given: Molar mass of ${BaSO}_{4}$ is 233 g ${mol}^{- 1}$ [2023]