The set of all α, for which the vectors a→=αti^+6j^–3k^ and b→=ti^–2j^–2αtk^ are inclined at an obtuse angle for all t∈R, is [2024]
(3)
Given, a→=αti^+6j^–3k^ and b→=ti^–2j^–2αtk^
So, a→·b→<0 ∀t∈R [∴ a→ and b→ are inclined at an obtuse angle]
⇒ αt2–12+6αt<0 ∀t∈R ⇒ α<0 and D<0
⇒ 36α2+48α<0 ⇒ 12α(3α+4)<0
⇒ –43<α<0
Also, for α=0, a→·b→<0 ⇒ α∈(–43,0].