The resistance of platinum wire at is 2 and 6.8 at . The temperature coefficient of resistance of the wire is [2023]

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Q.
The resistance of platinum wire at $0 ° C$ is 2 $Ω$ and 6.8 $Ω$ at $80 ° C$ . The temperature coefficient of resistance of the wire is [2023]

1 $3 \times 10^{- 2} {{}^{\circ}C}^{- 1}$

2 $3 \times 10^{- 1} {{}^{\circ}C}^{- 1}$

3 $3 \times 10^{- 4} {{}^{\circ}C}^{- 1}$

4 $3 \times 10^{- 3} {{}^{\circ}C}^{- 1}$

Ans.
(1)

Given, $R_{0} = 2 Ω$ at $T_{1} = 0 ° C$ and $R = 6.8 Ω$ at $T_{2} = 80 ° C$

As, $R = R_{0} [1 + α (T_{2} - T_{1})]$

$6.8 = 2 [1 + α (80 - 0)] \Rightarrow 6.8 = 2 + 160 α$

$α = 0.03 or 3 \times 10^{- 2} ° C^{- 1}$

Solution

Q.
The resistance of platinum wire at $0 ° C$ is 2 $Ω$ and 6.8 $Ω$ at $80 ° C$ . The temperature coefficient of resistance of the wire is [2023]

1 $3 \times 10^{- 2} {{}^{\circ}C}^{- 1}$

2 $3 \times 10^{- 1} {{}^{\circ}C}^{- 1}$

3 $3 \times 10^{- 4} {{}^{\circ}C}^{- 1}$

4 $3 \times 10^{- 3} {{}^{\circ}C}^{- 1}$

Ans.
(1)

Given, $R_{0} = 2 Ω$ at $T_{1} = 0 ° C$ and $R = 6.8 Ω$ at $T_{2} = 80 ° C$

As, $R = R_{0} [1 + α (T_{2} - T_{1})]$

$6.8 = 2 [1 + α (80 - 0)] \Rightarrow 6.8 = 2 + 160 α$

$α = 0.03 or 3 \times 10^{- 2} ° C^{- 1}$

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Solution

Q. The resistance of platinum wire at 0°C is 2Ω and 6.8Ω at 80°C. The temperature coefficient of resistance of the wire is [2023]

1 3×10-2C∘-1

2 3×10-1C∘-1

3 3×10-4C∘-1

4 3×10-3C∘-1

Ans. (1) Given, R0=2Ω at T1=0°C and R=6.8Ω at T2=80°C As, R=R0[1+α(T2-T1)] 6.8=2[1+α(80-0)]⇒6.8=2+160α α=0.03 or 3×10-2 °C-1

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Q.
The resistance of platinum wire at $0 ° C$ is 2 $Ω$ and 6.8 $Ω$ at $80 ° C$ . The temperature coefficient of resistance of the wire is [2023]

1 $3 \times 10^{- 2} {{}^{\circ}C}^{- 1}$

2 $3 \times 10^{- 1} {{}^{\circ}C}^{- 1}$

3 $3 \times 10^{- 4} {{}^{\circ}C}^{- 1}$

4 $3 \times 10^{- 3} {{}^{\circ}C}^{- 1}$

Ans.
(1)

Given, $R_{0} = 2 Ω$ at $T_{1} = 0 ° C$ and $R = 6.8 Ω$ at $T_{2} = 80 ° C$

As, $R = R_{0} [1 + α (T_{2} - T_{1})]$

$6.8 = 2 [1 + α (80 - 0)] \Rightarrow 6.8 = 2 + 160 α$

$α = 0.03 or 3 \times 10^{- 2} ° C^{- 1}$