Q.

The resistance of a wire is 5Ω. Its new resistance in ohm, if stretched to 5 times of its original length, will be              [2023]

1 125  
2 5  
3 25  
4 625  

Ans.

(1)

 Volume of wire is constant in stretching

      Vi=Vf

Aili=Aflf

Al=A'(5l)

A'=A5

Rf=ρlfAf=ρ(5l)(A5)=25(ρlA)=25×5=125 Ω