The resistance of a wire is 5 Ω. Its new resistance in ohm, if stretched to 5 times of its original length, will be [2023]
(1)
∴ Volume of wire is constant in stretching
Vi=Vf
Aili=Aflf
Al=A'(5l)
A'=A5
Rf=ρlfAf=ρ(5l)(A5)=25(ρlA)=25×5=125 Ω