The reading of pressure metre attached with a closed pipe is . On opening the valve, water starts flowing and the reading of pressure metre falls to . The velocity of water is found to be . The value of V is

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Solution

Q.
The reading of pressure metre attached with a closed pipe is $4.5 \times 10^{4} N / m^{2}$ . On opening the valve, water starts flowing and the reading of pressure metre falls to $2.0 \times 10^{4} N / m^{2}$ . The velocity of water is found to be $\sqrt{V} m / s$ . The value of V is ___________ . [2024]

Ans.
(50) $Change in pressure = \frac{1}{2} ρ v^{2}$

$4.5 \times 10^{4} - 2 \times 10^{4} = \frac{1}{2} \times 10^{3} \times v^{2}$

$2.5 \times 10^{4} = \frac{1}{2} \times 10^{3} \times v^{2}$

$v^{2} = 50$

$v = \sqrt{50}$

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