The ratio for the reaction | Chemical Equilibrium | JEE Main Chemistry Chapter Wise Question Papers

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Solution

Q.
The ratio $\frac{K_{P}}{K_{C}}$ for the reaction:

${CO}_{(g)} + \frac{1}{2} O_{2 (g)} ⇌ {CO}_{2 (g)}$ is : [2024]

1 $R T$

2 ${(R T)}^{1 / 2}$

3 $\frac{1}{\sqrt{R T}}$

4 1

Ans.
(3)

   $CO (g) + \frac{1}{2} O_{2} (g) ⇌ {CO}_{2} (g)$

   $Δ n_{g} = Gaseous mol of product - gaseous mol of reactant$

   $= 1 - (1 + 0.5) = - 0.5$

$K_{p} = K_{c} {(R T)}^{Δ n_{g}}$

$\frac{K_{p}}{K_{c}} = {(R T)}^{- 0.5} = \frac{1}{\sqrt{R T}}$

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