The ratio of the shortest wavelength of Balmer series to the shortest wavelength of Lyman series for hydrogen atom is

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Solution

Q.
The ratio of the shortest wavelength of Balmer series to the shortest wavelength of Lyman series for hydrogen atom is [2024]

1 2 : 1

2 1 : 4

3 1 : 2

4 4 : 1

Ans.
(4)

$For Balmer series limit, \frac{1}{λ_{B}} = R [\frac{1}{{(2)}^{2}} - \frac{1}{\infty^{2}}] = \frac{R}{4}$

$For Lyman series limit, \frac{1}{λ_{L}} = R [\frac{1}{{(1)}^{2}} - \frac{1}{\infty^{2}}] = R$

$\Rightarrow \frac{λ_{B}}{λ_{L}} = 4 : 1$

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