The radius of curvature of each surface of a convex lens having refractive index 1.8 is 20 cm. The lens is now immersed in a liquid of refractive index 1.5. [2023]

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Solution

Q.
The radius of curvature of each surface of a convex lens having refractive index 1.8 is 20 cm. The lens is now immersed in a liquid of refractive index 1.5. The ratio of power of lens in air to its power in the liquid will be $x : 1$ . The value of $x$ is ____ . [2023]

Ans.
(4)

$P = (1.8 - 1) (\frac{1}{20} + \frac{1}{20}) by lens maker's formula$

$P' = (\frac{1.8}{1.5} - 1) (\frac{1}{20} + \frac{1}{20})$

$Dividing \frac{P}{P'} = \frac{0.8}{1.2 - 1} = 4$

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