The pH of 0.01 M Naoh solution will be [2019]

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Solution

Q.
The pH of 0.01 M $N a O H_{(a q)}$ solution will be [2019]

1 7.01

2 2

3 12

4 9

Ans.
(3)

$\underset{0.01 M}{NaOH} \to {Na}^{+} + \underset{0.01 M}{{OH}^{-}}$

$∴$    $[{OH}^{-}] = 0.01$ $M$

$∴$    $pOH = - \log [{OH}^{-}] = - \log (0.01) = 2$

$∴$    $pH = 14 - pOH = 14 - 2 = 12$

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