The osmotic pressure of a dilute solution is Pa at 273 K. Osmotic pressure of the same solution at 283 K is

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Solution

Q.
The osmotic pressure of a dilute solution is $7 \times 10^{5}$ Pa at 273 K. Osmotic pressure of the same solution at 283 K is _______ $\times 10^{4} {Nm}^{- 2}$ . [2024]

Ans.
(73)

$Osmotic pressure(π) (for a non - electrolyte solution) is related to concentration (C) and temperature (T) as,$

$π = C R T, where R is universal gas constant$

$π_{1} = C R T_{1}, π_{2} = C R T_{2}$

$\frac{π_{2}}{π_{1}} = \frac{T_{2}}{T_{1}}$

   $\frac{π_{2}}{7 \times 10^{5} Pa} = \frac{283 K}{273 K}$

$π_{2} = 7 \times 10^{5} \times \frac{283}{273} Pa$

   $= 7.256 \times 10^{5} {Nm}^{- 2}$

   $= 72.56 \times 10^{4} {Nm}^{- 2}$

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