The number of solutions of the equation cos2θ cosθ2+cos5θ2=2cos35θ2in [–π2,π2] is: [2025]
(3)
We have, cos2θ cosθ2+cos5θ2=2cos35θ2
⇒ 12(2cos2θ cosθ2)+cos5θ2=12(cos15θ2+3cos5θ2)
⇒ 12(cos5θ2+cos3θ2)=cos5θ2cos5θ
⇒ cos5θ2+cos3θ2=cos15θ2+cos5θ2
⇒ cos3θ2=cos15θ2 ⇒ cos15θ2–cos3θ2=0
⇒ 2sin3θsin9θ2=0 ⇒ 3θ=nπ or 9θ2=mπ
⇒ θ=nπ3 or θ=2mπ9 for m, n∈Z
∴ θ={–π3,π3,0} and θ={–4π9,–2π9,0,2π9,4π9}
Required number of solutions = 7.