The number of moles of methane required to produce 11g (g) after complete combustion is:

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Solution

Q.
The number of moles of methane required to produce 11g $C O_{2}$ (g) after complete combustion is:

[Given molar mass of methane in g $m o l^{- 1}$ : 16] [2024]

1 0.75

2 0.5

3 0.35

4 0.25

Ans.
(4)

${CH}_{4} (g) + 2 O_{2} (g) \to {CO}_{2} (g) + 2 H_{2} O (l)$

$Moles of {CO}_{2} (n_{{CO}_{2}}) = \frac{Given mass}{Molar mass} = \frac{11 g}{44 g {mol}^{- 1}} = 0.25 mol$

By stoichiometry of reaction,

$Moles of {CH}_{4} (n_{{CH}_{4}}) = Moles of {CO}_{2} (n_{{CO}_{2}}) = 0.25 mol .$

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