The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is (charge on electron = 1.60×10-19 C) [2016]
(3)
Q=I×t
Q=1×60=60 C
Now, 1.6×10-19 C≡1 electron
∴ 60 C≡601.6×10-19=3.75×1020 electrons