The mass of zinc produced by the electrolysis of zinc sulphate solution with a steady current of 0.015 A for 15 minutes is

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Solution

Q.
The mass of zinc produced by the electrolysis of zinc sulphate solution with a steady current of 0.015 A for 15 minutes is ____ $\times 10^{- 4}$ g.

(Atomic mass of zinc = 65.4 amu) [2024]

Ans.
(46)

$C h a r g e (Q) = C u r r e n t (I) \times t i m e (t) = 0.015 A \times 15 m i n$

$= 0.015 A \times 15 \times 60 s = 13.5 C$

$M o l e s o f e l e c t r o n s (n_{e^{-}}) = \frac{Q}{c h a r g e o n 1 m o l e^{-}}$

$M o l e s o f e l e c t r o n s (n_{e^{-}}) = \frac{13.5 C}{96487 C} = 1.399 \times 10^{- 4} mol$

$R e a c t i o n a t c a t h o d e f o r e l e c t r o l y s i s o f Z n S O_{4} :$

${Zn}^{2 +} (aq) + 2 e^{-} \to Zn(s)$

$B y s t o i c h i o m e t r y :$

$\frac{n_{Zn}}{1} = \frac{n_{e^{-}}}{2}$

$n_{Zn} = \frac{1.399 \times 10^{- 4}}{2} mol$

$M a s s o f z i n c (W) = m o l e s o f Z n (n_{Z n}) \times m o l a r m a s s o f Z n (M_{Z n}) = \frac{1.399 \times 10^{- 4}}{2} \times 65.4 g = 45.75 \times 10^{- 4} g$

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