Q.

The mass defect in a particular reaction is 0.4 g. The amount of energy liberated is n×107 kWh, where n = ______. (speed of light = 3×108 m/s)          [2024]


Ans.

(1)        E=Δmc2

             =0.4×10-3×(3×108)2=3600×107kWs

              =3600×1073600kWh=1×107kWh