The magnetic potential due to a magnetic dipole at a point on its axis situated at a distance of 20 cm from its center is Tm. The magnetic moment of the dipole is

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Courses

CLASSROOM COURSES
ONLINE COURSES

ONLINE COURSES

More

Solution

Q.
The magnetic potential due to a magnetic dipole at a point on its axis situated at a distance of 20 cm from its center is $1.5 \times 10^{- 5}$ Tm. The magnetic moment of the dipole is _____. (Given: $μ_{0} / 4 π = 10^{- 7}$ $T m A^{- 1}$ ) [2024]

Ans.
(6) The magnetic potential due to a magnetic dipole,

$V = \frac{μ_{0}}{4 π} \frac{M}{r^{2}}$

$\Rightarrow 1.5 \times 10^{- 5} = 10^{- 7} \times \frac{M}{{(20 \times 10^{- 2})}^{2}}$

$\Rightarrow M = \frac{1.5 \times 10^{- 5} \times 20 \times 20 \times 10^{- 4}}{10^{- 7}}$

$M = 1.5 \times 4 = 6$

Want Us to Email you About Special Offers & Updates?