The magnetic moment is measured in Bohr Magneton (BM). Spin-only magnetic moment of Fe in [ Fe ( H 2 O ) 6 ] 3 + and [ Fe ( CN ) 6 ] 3 - complexes respectively is: [2023]

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Solution

Q.
The magnetic moment is measured in Bohr Magneton (BM). Spin-only magnetic moment of Fe in ${[Fe {(H_{2} O)}_{6}]}^{3 +}$ and ${[Fe {(CN)}_{6}]}^{3 -}$ complexes respectively is: [2023]

1 6.92 B.M. in both

2 4.89 B.M. and 6.92 B.M.

3 3.87 B.M. and 1.732 B.M.

4 5.92 B.M. and 1.732 B.M.

Ans.
(4)

${[Fe {(H_{2} O)}_{6}]}^{3 +}$

$Oxidation number of Fe = + 3$

${Fe}^{3 +} = 3 d^{5}; H_{2} O is W.F.L., so configuration is t_{2 g}^{1, 1, 1} e_{g}^{1, 1}$

$Number of unpaired electrons n = 5$

$Magnetic moment (spin only) μ = \sqrt{n (n + 2)} B.M.$

$So μ = \sqrt{35} B.M. = 5.92 B.M.$

${[Fe {(CN)}_{6}]}^{3 -}$

$Oxidation number of Fe = + 3$

${Fe}^{3 +} = 3 d^{5}; {CN}^{-} is S.F.L., so configuration is t_{2 g}^{2, 2, 1} e_{g}^{0, 0}$

$Number of unpaired electrons n = 1$

$Magnetic moment (spin only) μ = \sqrt{n (n + 2)} B.M.$

$So μ = \sqrt{3} B.M. = 1.73 B.M.$

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