The magnetic field inside a 200 turns solenoid of radius 10 cm is . If the solenoid carries a current of 0.29A, then the length of the solenoid is ______ cm. [2025]

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Solution

Q.
The magnetic field inside a 200 turns solenoid of radius 10 cm is $2.9 \times 10^{- 4} Tesla$ . If the solenoid carries a current of 0.29A, then the length of the solenoid is ______ $π$ cm. [2025]

Ans.
(8)

Assuming long solenoid, magnetic field inside a solenoid

$B = μ_{0} i (\frac{N}{L})$

$L = \frac{μ_{0} N i}{B} = \frac{4 π \times 10^{- 7} \times 200 \times 0.29}{2.9 \times 10^{- 4}} = 8 π cm$

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