Q.

The Least positive integral value of α, for which the angle between the vectors αi^–2j^+2k^ and αi^+2αj^–2k^ is acute, is __________.          [2024]


Ans.

(5)

cosθ=a→·b→|a→||b→|

As θ is acute, so cosθ>0.

(αi^–2j^+2k^)·(αi^+2αj^–2k^)α2+(–2)2+(2)2×α2+(2α)2+(–2)2>0

⇒ α2–4α–4α2+8×5α2+4>0

⇒ α2–4α–4>0 ⇒ α2–4α+4–4–4>0

⇒ (α–2)2–8>0 ⇒(α–2)2>8

⇒ α–2>22  or  α–2<–22          (Neglect)

⇒ α>2+22=4.83

⇒ Least positive integral value of α=5.