The internal energy of air in 4 m × 4 m × 3 m sized room at 1 atmospheric pressure will be _______ ×106 J. (Consider air as diatomic molecule) [2025]
(12)
U=nCvT=n×5R2T
⇒ U=52(nRT)=52PV
⇒ U=52×105×4×4×3=12×106J