Q.

The internal energy of air in 4 m × 4 m × 3 m sized room at 1 atmospheric pressure will be _______ ×106 J. (Consider air as diatomic molecule)        [2025]


Ans.

(12)

U=nCvT=n×5R2T

 U=52(nRT)=52PV

 U=52×105×4×4×3=12×106J