The initial speed of a projectile fired from ground is . At the highest point during its motion, the speed of the projectile is . The time of flight of the projectile is [2023]

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Solution

Q.
The initial speed of a projectile fired from ground is $u$ . At the highest point during its motion, the speed of the projectile is $\frac{\sqrt{3}}{2} u$ . The time of flight of the projectile is [2023]

1 $\frac{u}{2 g}$

2 $\frac{u}{g}$

3 $\frac{2 u}{g}$

4 $\frac{\sqrt{3} u}{g}$

Ans.
(2)

$u \cos θ = \frac{\sqrt{3} u}{2} \Rightarrow \cos θ = \frac{\sqrt{3}}{2} \Rightarrow θ = 30 °$

$Hence T = \frac{2 u \sin 30 °}{g} = \frac{u}{g}$

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