The increase in pressure required to decrease the volume of a water sample byy 0.2%, is , Bulk modulus of water is . The value of P is __________. [2025]

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Solution

Q.
The increase in pressure required to decrease the volume of a water sample by 0.2% is $P \times 10^{5} {Nm}^{- 2}$ . Bulk modulus of water is $2.15 \times 10^{9} {Nm}^{- 2}$ . The value of P is __________. [2025]

Ans.
(43)

Since bulk modulus is given as

$B = \frac{- △ P}{(\frac{△ V}{V})}$

$2.15 \times 10^{9} = \frac{- △ P}{- (\frac{0.2}{100})}$

$△ P = 2.15 \times 10^{9} \times 2 \times 10^{- 3} = 4.3 \times 10^{6} = 43 \times 10^{5} N / m^{2}$

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