The hydrogen electrode is dipped in a solution of pH = 3 at . The potential of the electrode will be

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Solution

Q.
The hydrogen electrode is dipped in a solution of pH = 3 at $25^{°} C$ . The potential of the electrode will be - ____ $\times 10^{- 2} V .$

$(\frac{2.303 R T}{F} = 0.059 V)$

Ans.
(18)

For hydrogen electrode at 1 bar and 298K

$E_{reduction} = - 0.059 pH = - 0.059 \times 3 = - 0.177 V$

$= - 17.7 \times 10^{- 2} V \approx - 18 \times 10^{- 2} V$

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