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Solution


Q.

The ground state energy of hydrogen atom is −13.6 eV. The energy needed to ionize hydrogen atom from its second excited state will be         [2023]
1 13.6 eV  
2 6.8 eV  
3 1.51 eV   
4 3.4 eV  

Ans.

(3)

The energy of nth state in the hydrogen atom will be En=-13.6 eVn2

For n=3;   E3=-13.6 eV9=-1.51 eV

So, ionization energy will be, -(-1.51) eV=1.51 eV