The geometry and magnetic behaviour of the complex are [2018]

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Q.
The geometry and magnetic behaviour of the complex $[Ni {(CO)}_{4}]$ are [2018]

1 square planar geometry and diamagnetic

2 tetrahedral geometry and diamagnetic

3 square planar geometry and paramagnetic

4 tetrahedral geometry and paramagnetic

Ans.
(2)

Ni(28) : [Ar] $3 d^{8} 4 s^{2}$

$∵$ CO is a strong field ligand, so, unpaired electrons get paired.

Thus, the complex is $s p^{3}$ hybridised with tetrahedral geometry and diamagnetic in nature.

Solution

Q.
The geometry and magnetic behaviour of the complex $[Ni {(CO)}_{4}]$ are [2018]

1 square planar geometry and diamagnetic

2 tetrahedral geometry and diamagnetic

3 square planar geometry and paramagnetic

4 tetrahedral geometry and paramagnetic

Ans.
(2)

Ni(28) : [Ar] $3 d^{8} 4 s^{2}$

$∵$ CO is a strong field ligand, so, unpaired electrons get paired.

Thus, the complex is $s p^{3}$ hybridised with tetrahedral geometry and diamagnetic in nature.

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Solution

Q. The geometry and magnetic behaviour of the complex [Ni(CO)4] are [2018]

1 square planar geometry and diamagnetic

2 tetrahedral geometry and diamagnetic

3 square planar geometry and paramagnetic

4 tetrahedral geometry and paramagnetic

Ans. (2) Ni(28) : [Ar] 3d84s2 ∵ CO is a strong field ligand, so, unpaired electrons get paired. Thus, the complex is sp3 hybridised with tetrahedral geometry and diamagnetic in nature.

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Q.
The geometry and magnetic behaviour of the complex $[Ni {(CO)}_{4}]$ are [2018]

Ans.
(2)

Ni(28) : [Ar] $3 d^{8} 4 s^{2}$

$∵$ CO is a strong field ligand, so, unpaired electrons get paired.

Thus, the complex is $s p^{3}$ hybridised with tetrahedral geometry and diamagnetic in nature.