The element Z = 114 has been discovered recently. It will belong to which of the following family/group and electronic configuration? [2017]

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Q.
The element Z = 114 has been discovered recently. It will belong to which of the following family/group and electronic configuration [2017]

1 Carbon family, [Rn] $5 f^{14} 6 d^{10} 7 s^{2} 7 p^{2}$

2 Oxygen family, [Rn] $5 f^{14} 6 d^{10} 7 s^{2} 7 p^{4}$

3 Nitrogen family, [Rn] $5 f^{14} 6 d^{10} 7 s^{2} 7 p^{6}$

4 Halogen family, [Rn] $5 f^{14} 6 d^{10} 7 s^{2} 7 p^{5}$

Ans.
(1)

The electronic configuration of the element with Z = 114 (Flerovium) is $[Rn] 5 f^{14} 6 d^{10} 7 s^{2} 7 p^{2} .$

Hence, it belongs to the carbon family which has the same outer electronic configuration.

Solution

Q.
The element Z = 114 has been discovered recently. It will belong to which of the following family/group and electronic configuration [2017]

1 Carbon family, [Rn] $5 f^{14} 6 d^{10} 7 s^{2} 7 p^{2}$

2 Oxygen family, [Rn] $5 f^{14} 6 d^{10} 7 s^{2} 7 p^{4}$

3 Nitrogen family, [Rn] $5 f^{14} 6 d^{10} 7 s^{2} 7 p^{6}$

4 Halogen family, [Rn] $5 f^{14} 6 d^{10} 7 s^{2} 7 p^{5}$

Ans.
(1)

The electronic configuration of the element with Z = 114 (Flerovium) is $[Rn] 5 f^{14} 6 d^{10} 7 s^{2} 7 p^{2} .$

Hence, it belongs to the carbon family which has the same outer electronic configuration.

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Solution

Q. The element Z = 114 has been discovered recently. It will belong to which of the following family/group and electronic configuration [2017]

1 Carbon family, [Rn] 5f146d107s27p2

2 Oxygen family, [Rn] 5f146d107s27p4

3 Nitrogen family, [Rn] 5f146d107s27p6

4 Halogen family, [Rn] 5f146d107s27p5

Ans. (1) The electronic configuration of the element with Z = 114 (Flerovium) is [Rn] 5f14 6d10 7s2 7p2. Hence, it belongs to the carbon family which has the same outer electronic configuration.

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Q.
The element Z = 114 has been discovered recently. It will belong to which of the following family/group and electronic configuration [2017]

1 Carbon family, [Rn] $5 f^{14} 6 d^{10} 7 s^{2} 7 p^{2}$

2 Oxygen family, [Rn] $5 f^{14} 6 d^{10} 7 s^{2} 7 p^{4}$

3 Nitrogen family, [Rn] $5 f^{14} 6 d^{10} 7 s^{2} 7 p^{6}$

4 Halogen family, [Rn] $5 f^{14} 6 d^{10} 7 s^{2} 7 p^{5}$

Ans.
(1)

The electronic configuration of the element with Z = 114 (Flerovium) is $[Rn] 5 f^{14} 6 d^{10} 7 s^{2} 7 p^{2} .$

Hence, it belongs to the carbon family which has the same outer electronic configuration.