The -electronic configuration of an octahedral Co(II) complex having magnetic moment of 3.95 BM is : [2025]

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Solution

Q.
The $d$ -electronic configuration of an octahedral Co(II) complex having magnetic moment of 3.95 BM is : [2025]

1 $t_{2 g}^{3} e_{g}^{0}$

2 $t_{2 g}^{5} e_{g}^{2}$

3 $e_{g}^{4} t_{2 g}^{3}$

4 $t_{2 g}^{6} e_{g}^{1}$

Ans.
(2)

Magnetic moment ( $μ$ ) = $\sqrt{n (n + 2)}$ BM = 3.95 BM, where $n$ = number of unpaired electrons.

This gives $n = 3$ .

Electronic configuration of $C o^{2 +}$ is ${}_{18}{[Ar]}$ $3 d^{7}$ , which splits into $t_{2 g}^{2, 2, 2} e_{g}^{1, 0} (for strong field ligand) or t_{2 g}^{2, 2, 1} e_{g}^{1, 1} (for weak field ligand) .$ $t_{2 g}^{2, 2, 1} e_{g}^{1, 1}$ has three unpaired electrons; hence, this is the correct answer.

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