The electric field in a plane electromagnetic wave is given by $E_{z} = 60 \cos (5 x + 1.5 \times 10^{9} t) V/m .$

Then expression for the corresponding magnetic field is (here subscripts denote the direction of the field) [2025]

Question

The electric field in a plane electromagnetic wave is given by $E_{z} = 60 \cos (5 x + 1.5 \times 10^{9} t) V/m .$

Then expression for the corresponding magnetic field is (here subscripts denote the direction of the field) [2025]

Smart Achievers · Accepted Answer

(3)

Given, $E_{z} = 60 \cos (5 x + 1.5 \times 10^{9} t)$ $V/m$

As, $B_{0} = \frac{E_{0}}{c} \Rightarrow B_{0} = \frac{60}{3 \times 10^{8}} = 2 \times 10^{- 7}$ $T$

Since, In an electromagnetic wave, the direction of wave propagation is along

$\vec{E} \times \vec{B}$ thus magnetic field will be along $y$ -direction.

$∴$ $B_{y} = 2 \times 10^{- 7} \cos (5 x + 1.5 \times 10^{9} t) J$

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