The electric field in a plane electromagnetic wave is given by Then expression for the corresponding magnetic field is (here subscripts denote the direction of the field) [2025]

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Q.
The electric field in a plane electromagnetic wave is given by $E_{z} = 60 \cos (5 x + 1.5 \times 10^{9} t) V/m .$

Then expression for the corresponding magnetic field is (here subscripts denote the direction of the field) [2025]

1 $B_{z} = 60 \cos (5 x + 1.5 \times 10^{9} t)$ $T$

2 $B_{y} = 60 \sin (5 x + 1.5 \times 10^{9} t)$ $T$

3 $B_{y} = 2 \times 10^{- 7} \cos (5 x + 1.5 \times 10^{9} t)$ $T$

4 $B_{x} = 2 \times 10^{- 7} \cos (5 x + 1.5 \times 10^{9} t)$ $T$

Ans.
(3)

Given, $E_{z} = 60 \cos (5 x + 1.5 \times 10^{9} t)$ $V/m$

As, $B_{0} = \frac{E_{0}}{c} \Rightarrow B_{0} = \frac{60}{3 \times 10^{8}} = 2 \times 10^{- 7}$ $T$

Since, In an electromagnetic wave, the direction of wave propagation is along

$\vec{E} \times \vec{B}$ thus magnetic field will be along $y$ -direction.

$∴$ $B_{y} = 2 \times 10^{- 7} \cos (5 x + 1.5 \times 10^{9} t) J$

Solution

Q.
The electric field in a plane electromagnetic wave is given by $E_{z} = 60 \cos (5 x + 1.5 \times 10^{9} t) V/m .$

Then expression for the corresponding magnetic field is (here subscripts denote the direction of the field) [2025]

1 $B_{z} = 60 \cos (5 x + 1.5 \times 10^{9} t)$ $T$

2 $B_{y} = 60 \sin (5 x + 1.5 \times 10^{9} t)$ $T$

3 $B_{y} = 2 \times 10^{- 7} \cos (5 x + 1.5 \times 10^{9} t)$ $T$

4 $B_{x} = 2 \times 10^{- 7} \cos (5 x + 1.5 \times 10^{9} t)$ $T$

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Solution

Q. The electric field in a plane electromagnetic wave is given by Ez=60cos(5x+1.5×109t) V/m. Then expression for the corresponding magnetic field is (here subscripts denote the direction of the field) [2025]

1 Bz=60cos(5x+1.5×109t)T

2 By=60sin(5x+1.5×109t)T

3 By=2×10-7cos(5x+1.5×109t)T

4 Bx=2×10-7cos(5x+1.5×109t)T

Ans. (3) Given, Ez=60cos(5x+1.5×109t)V/m As, B0=E0c⇒B0=603×108=2×10-7T Since, In an electromagnetic wave, the direction of wave propagation is along E→×B→ thus magnetic field will be along y-direction. ∴ By=2×10-7cos(5x+1.5×109t) J

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Q.
The electric field in a plane electromagnetic wave is given by $E_{z} = 60 \cos (5 x + 1.5 \times 10^{9} t) V/m .$

Then expression for the corresponding magnetic field is (here subscripts denote the direction of the field) [2025]

1 $B_{z} = 60 \cos (5 x + 1.5 \times 10^{9} t)$ $T$

2 $B_{y} = 60 \sin (5 x + 1.5 \times 10^{9} t)$ $T$

3 $B_{y} = 2 \times 10^{- 7} \cos (5 x + 1.5 \times 10^{9} t)$ $T$

4 $B_{x} = 2 \times 10^{- 7} \cos (5 x + 1.5 \times 10^{9} t)$ $T$