The effect of addition of helium gas to the following reaction in equilibrium state, is: [2023]

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Solution

Q.
The effect of addition of helium gas to the following reaction in equilibrium state, is: ${PCl}_{5} (g) ⇌ {PCl}_{3} (g) + {Cl}_{2} (g)$ [2023]

1 Addition of helium will not affect the equilibrium.

2 The equilibrium will shift in the forward direction and more of ${Cl}_{2}$ and ${PCl}_{3}$ gases will be produced.

3 The equilibrium will go backward due to suppression of dissociation of ${PCl}_{5}$ .

4 Helium will deactivate ${PCl}_{5}$ and reaction will stop.

Ans.
(2)

At constant pressure equilibrium shift where number of moles of gas increases so this reaction goes forward direction.

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Solution

Q. The effect of addition of helium gas to the following reaction in equilibrium state, is: PCl5(g)⇌PCl3(g)+Cl2(g) [2023]

1 Addition of helium will not affect the equilibrium.

2 The equilibrium will shift in the forward direction and more of Cl2 and PCl3 gases will be produced.

3 The equilibrium will go backward due to suppression of dissociation of PCl5.

4 Helium will deactivate PCl5 and reaction will stop.

Ans. (2) At constant pressure equilibrium shift where number of moles of gas increases so this reaction goes forward direction.

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Q.
The effect of addition of helium gas to the following reaction in equilibrium state, is: ${PCl}_{5} (g) ⇌ {PCl}_{3} (g) + {Cl}_{2} (g)$ [2023]

2 The equilibrium will shift in the forward direction and more of ${Cl}_{2}$ and ${PCl}_{3}$ gases will be produced.

3 The equilibrium will go backward due to suppression of dissociation of ${PCl}_{5}$ .

4 Helium will deactivate ${PCl}_{5}$ and reaction will stop.

Ans.
(2)

At constant pressure equilibrium shift where number of moles of gas increases so this reaction goes forward direction.