The density of 1 M solution of compound ‘X’ is 1.25 g . The correct option for the molality of solution is (Molar mass of compound, X = 85 g ) [2023]

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Solution

Q.
The density of 1 M solution of compound ‘X’ is 1.25 g ${mL}^{- 1}$ . The correct option for the molality of solution is

(Molar mass of compound, X = 85 g ${mol}^{- 1}$ ) [2023]

1 0.705 m

2 1.208 m

3 1.165 m

4 0.858 m

Ans.
(4)

$m = \frac{1000 \times M}{1000 \times d - (M M_{w})}$

Here, M = molarity of the solution, d = density of solution, $M_{w}$ = molar mass of the solute.

$m = \frac{1000 \times 1}{(1000 \times 1.25) - (1 \times 85)} = \frac{1000}{1165} = 0.858 m$

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