The current required to be passed through a solenoid of 15 cm length and 60 turns in order to demagnetise a bar magnet of magnetic intensity is _________ A. [2023]

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Solution

Q.
The current required to be passed through a solenoid of 15 cm length and 60 turns in order to demagnetise a bar magnet of magnetic intensity $2.4 \times 10^{3} {Am}^{- 1}$ is _________ A. [2023]

Ans.
(6)

$I = H$

$Given, I = 2.4 \times 10^{3} A/m$

$2.4 \times 10^{3} = H = n i$

$Number of turns per unit length, n = \frac{N}{ℓ}$

$2.4 \times 10^{3} = \frac{60}{15 \times 10^{- 2}} i$

$i = \frac{2.4 \times 15 \times 10}{60} = \frac{36}{6} = 6 A$

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