Q.

The current in an inductor is given by I=(3t+8) where t is in second. The magnitude of induced emf produced in the inductor is 12 mV. The self-inductance of the inductor ________ mH.                 [2024]


Ans.

(4)      |∈|=Ldidt

          i=|3t+8|⇒didt=3

          ε=12mV

          |ε|=L|dIdt|⇒12=L×3

          L=4mH