The critical angle for a denser-rarer interface is . The speed of light in rarer medium is . The speed of light in the denser medium is [2023]

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Q.
The critical angle for a denser-rarer interface is $45 °$ . The speed of light in rarer medium is $3 \times 10^{8} ms$ . The speed of light in the denser medium is [2023]

1 $5 \times 10^{7} m/s$

2 $2.12 \times 10^{8} m/s$

3 $3.12 \times 10^{7} m/s$

4 $\sqrt{2} \times 10^{8} m/s$

Ans.
(2)

$i_{C}$ = Critical angle

$\frac{v}{C} = \frac{1}{μ} = \sin i_{C} = \sin 45 ° = \frac{1}{\sqrt{2}}$

$\Rightarrow v = \frac{C}{\sqrt{2}} = \frac{3 \times 10^{8}}{\sqrt{2}} m/s = 2.12 \times 10^{8} m/s$

Solution

Q.
The critical angle for a denser-rarer interface is $45 °$ . The speed of light in rarer medium is $3 \times 10^{8} ms$ . The speed of light in the denser medium is [2023]

1 $5 \times 10^{7} m/s$

2 $2.12 \times 10^{8} m/s$

3 $3.12 \times 10^{7} m/s$

4 $\sqrt{2} \times 10^{8} m/s$

Ans.
(2)

$i_{C}$ = Critical angle

$\frac{v}{C} = \frac{1}{μ} = \sin i_{C} = \sin 45 ° = \frac{1}{\sqrt{2}}$

$\Rightarrow v = \frac{C}{\sqrt{2}} = \frac{3 \times 10^{8}}{\sqrt{2}} m/s = 2.12 \times 10^{8} m/s$

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Solution

Q. The critical angle for a denser-rarer interface is 45°. The speed of light in rarer medium is 3×108 ms. The speed of light in the denser medium is [2023]

1 5×107 m/s

2 2.12×108 m/s

3 3.12×107 m/s

4 2×108 m/s

Ans. (2) iC = Critical angle vC=1μ=siniC=sin45°=12 ⇒ v=C2=3×1082m/s=2.12×108 m/s

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Q.
The critical angle for a denser-rarer interface is $45 °$ . The speed of light in rarer medium is $3 \times 10^{8} ms$ . The speed of light in the denser medium is [2023]

1 $5 \times 10^{7} m/s$

2 $2.12 \times 10^{8} m/s$

3 $3.12 \times 10^{7} m/s$

4 $\sqrt{2} \times 10^{8} m/s$

Ans.
(2)

$i_{C}$ = Critical angle

$\frac{v}{C} = \frac{1}{μ} = \sin i_{C} = \sin 45 ° = \frac{1}{\sqrt{2}}$

$\Rightarrow v = \frac{C}{\sqrt{2}} = \frac{3 \times 10^{8}}{\sqrt{2}} m/s = 2.12 \times 10^{8} m/s$