The correct order of the number of unpaired electrons in the given complexes is A. [ Fe ( CN ) 6 ] 3 - B. [ FeF 6 ] 3 - C. [ CoF 6 ] 3 - D. [ Cr ( oxalate ) 3 ] 3 - E. [ Ni ( CO ) 4 ] ?? [2023]

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Solution

Q.
The correct order of the number of unpaired electrons in the given complexes is

A. ${[Fe {(CN)}_{6}]}^{3 -}$

B. ${[{FeF}_{6}]}^{3 -}$

C. ${[{CoF}_{6}]}^{3 -}$

D. ${[Cr {(oxalate)}_{3}]}^{3 -}$

E. $[Ni {(CO)}_{4}]$

Choose the correct answer from the options given below: [2023]

1 A < E < C < B < D

2 E < A < D < C < B

3 E < A < B < D < C

4 A < E < D < C < B

Ans.
(2)

$(A) {Fe}^{3 +} : 3 d^{5} : t_{2 g}^{2, 2, 1} e_{g}^{0, 0} \Rightarrow n = 1$

$(B) {Fe}^{3 +} : 3 d^{5} : t_{2 g}^{1, 1, 1} e_{g}^{1, 1} \Rightarrow n = 5$

$(C) {Co}^{3 +} : 3 d^{6} : t_{2 g}^{2, 1, 1} e_{g}^{1, 1} \Rightarrow n = 4$

$(D) {Cr}^{3 +} : 3 d^{3} : t_{2 g}^{1, 1, 1} e_{g}^{0} \Rightarrow n = 3$

$(E) {Ni}^{0} : 4 s^{2} 3 d^{8} : t_{2 g}^{2, 2, 2} e_{g}^{2, 2} \Rightarrow n = 0$

Hence, correct order is $E < A < D < C < B$

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