The correct order of dipole moments for molecules NH3, H2S, CH4 and HF , is [2023]

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Courses

CLASSROOM COURSES
ONLINE COURSES

ONLINE COURSES

Q.
The correct order of dipole moments for molecules ${NH}_{3}, H_{2} S, {CH}_{4}$ and $HF$ , is [2023]

1 ${CH}_{4} > H_{2} S > {NH}_{3} > HF$

2 $H_{2} S > {NH}_{3} > HF > {CH}_{4}$

3 ${NH}_{3} > HF > {CH}_{4} > H_{2} S$

4 $HF > {NH}_{3} > H_{2} S > {CH}_{4}$

Ans.
(4)

A given molecule posses dipole moment as a result of polarisation. Polarisation arises in a heteronuclear molecule due to significant electronegativity difference between atoms involved in covalent bond formation. The shared electron pair gets displaced towards more electronegative atom and the resultant covalent bond is polar covalent bond.

Thus, the correct order is: $HF > {NH}_{3} > H_{2} S > \underset{(Non - polar)}{{CH}_{4}}$

Solution

Q.
The correct order of dipole moments for molecules ${NH}_{3}, H_{2} S, {CH}_{4}$ and $HF$ , is [2023]

1 ${CH}_{4} > H_{2} S > {NH}_{3} > HF$

2 $H_{2} S > {NH}_{3} > HF > {CH}_{4}$

3 ${NH}_{3} > HF > {CH}_{4} > H_{2} S$

4 $HF > {NH}_{3} > H_{2} S > {CH}_{4}$

Want Us to Email you About Special Offers & Updates?

Solution

Q. The correct order of dipole moments for molecules NH3,H2S,CH4 and HF, is [2023]

1 CH4>H2S>NH3>HF

2 H2S>NH3>HF>CH4

3 NH3>HF>CH4>H2S

4 HF>NH3>H2S>CH4

Want Us to Email you About Special Offers & Updates?

Q.
The correct order of dipole moments for molecules ${NH}_{3}, H_{2} S, {CH}_{4}$ and $HF$ , is [2023]

1 ${CH}_{4} > H_{2} S > {NH}_{3} > HF$

2 $H_{2} S > {NH}_{3} > HF > {CH}_{4}$

3 ${NH}_{3} > HF > {CH}_{4} > H_{2} S$

4 $HF > {NH}_{3} > H_{2} S > {CH}_{4}$