The constant term in the expansion of (2x+1x7+3x2)5 is _______. [2023]
(1080)
General term=5!r1! r2! r3!(2x)r1(x-7)r2(3x2)r3
=5!r1! r2! r3!2r1·3r3·xr1-7r2+2r3
For the constant term, r1-7r2+2r3=0 and r1+r2+r3=5
By hit and trial, r1=1, r2=1 and r3=3.
∴ Constant term=5!1! 1! 3!21·33
=1206×2×27=20×2×27=1080