Q.

The constant term in the expansion of (2x+1x7+3x2)5 is _______.                  [2023]


Ans.

(1080)

General term=5!r1!r2!r3!(2x)r1(x-7)r2(3x2)r3

=5!r1!r2!r3!2r1·3r3·xr1-7r2+2r3

For the constant term, r1-7r2+2r3=0 and r1+r2+r3=5

By hit and trial, r1=1, r2=1 and r3=3.

  Constant term=5!1!1!3!21·33

                                   =1206×2×27=20×2×27=1080