The bond dissociation energies of and XY are in the ratio of 1 : 0.5 : 1. for the formation of XY is -200 kJ . The bond dissociation energy of will be [2018]

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Q.
The bond dissociation energies of $X_{2}, Y_{2}$ and XY are in the ratio of 1 : 0.5 : 1. $Δ H$ for the formation of XY is -200 kJ ${mol}^{- 1}$ . The bond dissociation energy of $X_{2}$ will be [2018]

1 $200$ $kJ$ ${mol}^{- 1}$

2 $100$ $kJ$ ${mol}^{- 1}$

3 $800$ $kJ$ ${mol}^{- 1}$

4 $400$ $kJ$ ${mol}^{- 1}$

Ans.
(3)

Let B.E. of $X_{2}, Y_{2}$ , and XY be $x$ $kJ$ ${mol}^{- 1}$ , $0.5 x$ $kJ$ ${mol}^{- 1}$ , and $x$ $kJ$ ${mol}^{- 1}$ respectively.

$\frac{1}{2} X_{2} + \frac{1}{2} Y_{2} \to X Y; Δ H = - 200$ $kJ$ ${mol}^{- 1}$

$Δ H = \sum ({B.E.)}_{Reactants} - \sum ({B.E.)}_{_{Products}}$

$∴$ $- 200 = [\frac{1}{2} \times (x) + \frac{1}{2} \times (0.5 x)] - [1 \times (x)]$

$B.E. of X_{2} = x = 800$ $kJ$ ${mol}^{- 1}$

Solution

Q.
The bond dissociation energies of $X_{2}, Y_{2}$ and XY are in the ratio of 1 : 0.5 : 1. $Δ H$ for the formation of XY is -200 kJ ${mol}^{- 1}$ . The bond dissociation energy of $X_{2}$ will be [2018]

1 $200$ $kJ$ ${mol}^{- 1}$

2 $100$ $kJ$ ${mol}^{- 1}$

3 $800$ $kJ$ ${mol}^{- 1}$

4 $400$ $kJ$ ${mol}^{- 1}$

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Solution

Q. The bond dissociation energies of X2,Y2 and XY are in the ratio of 1 : 0.5 : 1. ΔH for the formation of XY is -200 kJ mol-1. The bond dissociation energy of X2 will be [2018]

1 200 kJ mol-1

2 100 kJ mol-1

3 800kJ mol-1

4 400 kJ mol-1

Ans. (3) Let B.E. of X2,Y2, and XY be x kJ mol-1, 0.5x kJ mol-1, and x kJ mol-1 respectively. 12X2+12Y2→XY; ΔH=-200 kJ mol-1 ΔH=∑(B.E.)Reactants-∑(B.E.)Products ∴ -200=[12×(x)+12×(0.5x)]-[1×(x)] B.E. of X2=x=800 kJ mol-1

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Q.
The bond dissociation energies of $X_{2}, Y_{2}$ and XY are in the ratio of 1 : 0.5 : 1. $Δ H$ for the formation of XY is -200 kJ ${mol}^{- 1}$ . The bond dissociation energy of $X_{2}$ will be [2018]

1 $200$ $kJ$ ${mol}^{- 1}$

2 $100$ $kJ$ ${mol}^{- 1}$

3 $800$ $kJ$ ${mol}^{- 1}$

4 $400$ $kJ$ ${mol}^{- 1}$