The area of the region {(x,y):|x–y|≤y≤4x} is [2025]
(3)
We have, |x–y|≤y≤4x
Now, y=|x–y|⇒ y2=(x–y)2
⇒ y=x2 and x=0
Required Area =∫064(4x–x2)dx
=[4x3/23/2–x24]064=83·83–6424=642(112)=10243.