Q.

The area of the region {(x,y):|x–y|≤y≤4x} is          [2025]

1 512  
2 20483  
3 10243  
4 5123  

Ans.

(3)

We have, |x–y|≤y≤4x

Now, y=|x–y|⇒ y2=(x–y)2

⇒ y=x2 and x=0

Required Area =∫064(4x–x2)dx

=[4x3/23/2–x24]064=83·83–6424=642(112)=10243.