• 072920 77839
  • info@smartachievers.in
Menu
Back
  • JEE ADVANCE
  • JEE MAIN
  • NEET
  • BITSAT
  • CBSE BOARD
  • UP BOARD
  • CUET
JEE ADVANCE
  • CLASS XI - XII
  • CRASH COURSE
CRASH COURSE
JEE MAIN
  • CLASS XI - XII
  • CRASH COURSE
CRASH COURSE
NEET
  • CLASS XI - XII
  • CRASH COURSE
BITSAT
  • CLASS XI - XII
CBSE BOARD
  • CLASS IX
  • CLASS X
  • CLASS XI
  • CLASS XII
  • CLASS VI
  • CLASS VII
  • CLASS VIII
UP BOARD
  • CLASS IX
  • CLASS X
  • CLASS XI
  • CLASS XII
CUET
  • CRASH COURSE
Courses


Solution


Q.

A ‘circus’ is a company of performers who put on shows of acrobats, clowns, etc to entertain people. Started around 250 years back in open fields, now generally performed in tents. One such ‘Circus Tent’ is shown in figure. The tent is in the shape of a cylinder surmounted by a conical top. The height and diameter of cylindrical part are 9 m and 30 m respectively and height of conical part is 8 m with same diameter as that of the cylindrical part.

Based on the above information, answer the following questions:

 

(i) the area of the canvas used in making the tent.
1 1650 m2  
2 -1650 m2  
3 1550 m2  
4 1630 m2  

Ans.

(1)

We have,
Radius of cylindrical portion = radius of conical part = 15 m ⇒r=15 m

and, height of cylindrical part ,h=9 m

Also, height of conical portion, H=8 m

Slant height of cone

l=15)2+(8)2=225+64=289=17 m∴Area of canvas used in making tent

=CSA of cylinder+CSA of cone=2πrh+πrl

=2×227×15×9 + 227×15×17=848.57+801.43=1650 m2